I really need some help on how this stuff works, i know that you have to find what the ';N';, can some one tell me how to do that?How does this work? (5n = 2n + 6)?
5n=2n+6
5n-2n=2n-2n+6
3n=6
3/3n=6/3
n=2How does this work? (5n = 2n + 6)?
5n=2n+6
5n-2n=6
3n=6
n=6:3
n=2
5n = 2n + 6 (subtract 2n from both sides)
5n - 2n = 2n + 6 - 2n
3n = 6 (divide both sides by 3 to undo the multiplication)
3n/3 = 6/3
n = 2
Check:
5(2) = 2(2) + 6
10 = 4 + 6
10 = 10 (this is true, therefore n = 2 is correct)
Answer: n = 2
*Remember that the main goal is to isolate the variable on one side of the equation. In order to do this, simply apply the opposite operation of what is being done. In other words, when there is addition, use subtraction, and when there is multiplication, use division (and vice versa) when necessary.
5n = 2n + 6
First you need to group the n's together. You do this by bringing 2n over the the left hand side. When you bring a positive value from the right side of the ';='; sign to the left side (or vice versa) the positive value becomes negative.
Hence 5n-2n = 6
3n = 6
divide both sides by 3
n=6
I hope this is clear enough (:
First you must comine the n's. You can do this by subtracting 2n from both sides: 5n-2n = 2n+6-2n
3n=6
Then you must get the n all by itself. Do this by dividing both sides by 3
3n/3=6/3
n=2
First Step: 5n=2n+6
Second Step: 5n-2n=6
Third Step: 3n=6
Fourth Step: n = 6/3
n=2
Now put 2 (ur answer) back in the equation...
5 * 2 = 2*2 + 6
10 = 10
~*~Also I found a good website that has several examples u can click on and it'll tell u how to go about solving it I def recommend it!~*~
http://www.algebasics.com/3way2.html
im sorry if i'm being stupid....
5n=2n+6
5n-2n=6
3n=6
n=2
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