Bob has Jon have the same number of candies. Bob has 6 boxes of candies and two individual candies. Jon has 3 boxes of candies and 20 individual candies. How many candies are in a box?
I don't get it. I realize it's a system question, so here is my system.
let y = individual candy
let x = box of candy
6x+2y
3x+20y
But that doesn't make any sense because there are no equal signs in it so you cannot solve it. Thanks for any help!How do you work out this problem?
Actually, this is NOT a system of equations. An individual candy is just that, 1 candy. Since the only thing we're counting is candy, it's a unit, just like the number 1.
So instead, x represents the amount of candy in a box. Knowing that both boys have equal amounts allows an equation to be written.
Bob = Jon
6x + 2 = 3x + 20
Assuming you are comfortable with variables on each side, proceed from there. If not, please ask for further help.How do you work out this problem?
Well, Bob and Jon both have the same amount of candy so you set them equal to each other. Also, since x represents individual candies, x=1.
so set the two equations equal to each other.
6y + 2 = 3y + 20
3y + 2 = 20
3y = 18
y=6
6 candies per box.
Check:
6(6) + 2 = 38
3(6) + 20 = 38
Hope this helps!
You only need the X variable which will represent the candy in the box.
Set the two equations equal to each other since we know Bob and Jon have the same amount of candy
6x+2 = 3x +20
Subtract 3x from both sides
3x + 2 = 20
Subtract 2 from both sides
3x = 18
Divide both sides by 3
x = 6 candies in each box.
6x+2y=3x+20y (you do the equal sign because you know they have
the same amount of candy.)
6x+2=3x+20 (the y's represent a piec of candy so they are one
abd you really don't need them)
6x+2=3x+20
-2y -2y (isolate the x because you want candies per box)
6x=3x+18
-3x -3x
3x=18 (get two numbers)
3x/3 18/3
x=6
6 candies per box
Let X = the number of candies in a box
Therefore 6X + 2 = 3X + 20
3X = 18
X = 6
There are 6 candies in a box
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment